14g of CO at 27c is mixed with 16g of O2 at 47c. the temperature of the mixture is

No of moles of CO = mass/molar mass = 14/28 = 0.5 mole

No of moles of O2 = 16/32 = 0.5 mole

Since both have same no. of moles, the resulting temperature will be the average of both their temperatures.

..The temperature of the mixture is = (27+47)/2 = 37oC
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wrong answer
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Correct
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Right
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Ans:37°C

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No of moles of CO = mass/molar mass = 14/28 = 0.5 mole

No of moles of O2?= 16/32 = 0.5 mole

Since both have same no. of moles, the resulting temperature will be the average of both their temperatures.

...?The temperature of the mixture is = (27+47)/2 =?37oC
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calculate the angular speed and the mean kinetic energy 1 gram molecules of hydrogen at STP given density of hydrogen at STP in 0.09 Kilogram metre cube and R = 8.31j molper 1 k per1
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