15 The path difference between the two waves y1=a1sin(wt-2piex/lamda) and y2=a2cos(wt-2piex/lamda +theeta) is - Physics - Electromagnetic Waves

Question

15 The path difference between the two waves
y1=a1sin(wt-2piex/lamda) and y2=a2cos(wt-2piex/lamda +theeta)
is

Vara · Accepted Answer

The phase difference between the given waves with sin and cos
functions is equal to 90 degrees
The path difference corresponding to a phase difference of 180
degrees is equal to wavelength
Hence, the path difference corresponding to the path difference
of 90 degrees in the given problem is equal to half of the
wavelength, that is, λ2

15.The path difference between the two waves y1=a1sin(wt-2piex/lamda) and y2=a2cos(wt-2piex/lamda +theeta) is