150 mL of a gas at NTP were taken to 20^o C and 0.96 bar pressure. What is the change in volume of the gas?

Hi,

NTP is 20^oC (293.15 K) and 1 atm

1atm=1.01325bar

Thus the temperature has remained constant during the transition

thus we can use the equation

P₁V₁=P₂V₂

150 ×1.01325= 0.96 × V₂

V₂=158.32mL