1g of charcoal having surface area 3.02*10?m?is mixed in 100 ml of 0.5 M acetic acid solution; after few times concentration of solution becomes 0.49 M what will be surface area occupied one molecule of acetic acid ?

moles=molarity x volume (L)
         = (0.5 - 0.49) x 100 x 10-3
         = 10-3 moles
         = 10-3 x NA
         = 6.02 x 1020 molecules
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