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(2/3)10+ (3/2)10= (2/5)2n-2

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ln[(2/3)^10 + (3/2)^10]= (2n-1)ln(2/5)
ln[(2/3)^10 + (3/2)^10]/ ln (2/5) = 2n-1
and so n= [ln[(2/3)^10 + (3/2)^10]/ ln (2/5) + 1]/2

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