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2(iii)

2(iii) An ne Also. AB' r," - (2b And. AC2 - (6 60. AB2 AC' and therefore; AABC right angled B. Hence, AABC is an isosceles right triangle. EXERCISE 21C 1. Find the distance between the points : (i) A (7, 1.3) and B (10, 9) (iii P 4, 7) and Q (2.-5) (iii) C (4, -5) and D (12, -11) (iv) E 6. -4) and F (9, -12) 2. Find the distance of each Of the following points from the origin : Geometry

its so easy take formal root of x sq.and y sq .. do it
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Coordinates of origin is O(0,0)
Therefore OC=[(0-4)^2 + (0+6)^2]^(1/2) = [4^2 + 6^2]^(1/2)= [16+36]^(1/2) = 52^(1/2) = 7.211
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So easy root under x2 - x1 + y2 - y1
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It is very easy,
We will use Pythagorean theorem and
4?4 + 6?6 = side ? side
16 + 36 = side ? side
52 = side ? side
Side = ?52
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It's right answer

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Apply distance formula

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?x^2+y^2
= ?4^2+(-6)^2
=?16+36
=?52
=2?13 (Distance from the origin)
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