2. In triangle ABC, DE || BC and AD = 4cm, AB = 9cm. AC = 13.5 cm

then the value of EC is

(a) 6 cm (b) 7.5 cm (c) 9 cm (d) none of these

In triangle ABC ,DE// BC

Therefore, By BPT

AD/DB=AE/EC (1)

But AD/AB=4/9 (2)

AB/AD=9/4 -------------(By Invertendo)

AB-AD/AD=9-4/4 -----------(By Dividendo)

BD/AD=5/4 --------(A-D-B)

AD/DB=4/5 -------(By Invertendo)

Similarly AE/EC=4/9 (From 1 and 2)

AE+EC/EC=4+9/9 ----------(By Componendo)

AC/EC=13/9 (A-E-C)

13.5/EC=13/9

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In triangle ABC ,DE// BC

Therefore, By BPT

AD/DB=AE/EC (1)

now 4/9=AE/13.5

=AE=13.5*4/9=6

Now AC=AE+EC=EC=AC-AE=13.5-6=7.5

  • -3
so the correct option is none of these
  • 0
Given,
DEIIBC
AB=9cm
AD=4cm
AC=13.5cm
wkt,
AD+BD=AB
4cm+BD=9cm
BD=5cm
BD=EC  (as DE and BC are parellel)
So, EC=5cm
  • -3
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