2 mole of a ideal gas at 2 bar and 27 deg celcius expands isothermally against a constant pressure of  1 bar. the work done by the gas is equal to

Dear Student,

w=-nRTln (P1P2)Here, n=2R=8.314 JK-1mol-1T=27°C=27+273=300 KP1= 2 barP2= 1 barTherefore, w=-(2)(8.314)(300)ln21or, w=(-2)(8.314)(300)(ln2) = -3457.69 J =-34.57 kJ

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