2 mole of an ideal gas at 27 degree celcius and 1 atm pressure expand isothermally and reversibly till its pressure becomes 0.25 atm . calculate q , w and delta u
In a reversible isothermal expansion of a gas,at constant temperature,
T = 273 + 27 = 300K and n = 2
At constant temperature,
ΔU = 0 (First law of thermodyanamics, ΔU = q + W,and for irreversible process q=-W)
and,
W= -q = 68.21J
T = 273 + 27 = 300K and n = 2
At constant temperature,
ΔU = 0 (First law of thermodyanamics, ΔU = q + W,and for irreversible process q=-W)
and,
W= -q = 68.21J