2 spherical conductor each of capacity C are charged to potential V and -V .these are then connected by means of fine wire the loss of energy

a)0

b)(CV²)/2

c)CV²

d)2CV²

Question

2 spherical conductor each of capacity C are charged to
potential V and -V these are then connected by means of fine wire
the loss of energy
a)0
b)(CV2)/2
c)CV2
d)2CV2

Hansraj Rai · Accepted Answer

Initially the total energy of the system is =

$E = \frac{1}{2} C V^{2} + \frac{1}{2} C {(- V)}^{2} = C V^{2}$

Final potential of both the capacitors is = V - (-V) = 2V

Total capacitance is equal to the series combination of the two capacitors.

C' = C/2

Final potential energy of the system is,

$E' = \frac{1}{2} C' (2 {) V}^{2} = C V^{2}$

Loss of energy = E' - E = 0

2 spherical conductor each of capacity C are charged to potential V and -V .these are then connected by means of fine wire the loss of energy a)0 b)(CV2)/2 c)CV2 d)2CV2

2 spherical conductor each of capacity C are charged to potential V and -V .these are then connected by means of fine wire the loss of energy

a)0

b)(CV²)/2

c)CV²

d)2CV²