20 g of magnesium carbonate sample decomposes on heating to giv carbon dioxide and 8 g of magnesium oxide . what will be the percentage purity in this sample//? Share with your friends Share 57 Geetha answered this MgCO3 →∆ MgO + CO224 + 12 + 48 24 + 16 =84 g =40 g84 g of MgCO3 gives 40 g of MgO 20 g of MgCO3 gives = 4084 × 20 = 9.523 gSo if 100 % purity means 9.523 g of MgO is formed from 20 g of MgCO3But its given that 8 g only produced.So the % purity = 1009.523 × 8 =84 % 163 View Full Answer
