21) the ionisation potential of hydrogen atom is 13.6eV.Find out i)wavelength of H beta line in balmer seriesii)shortest wavelength of lyman series.

(1) Balmer series , beta line:E= 13.6(122-142) = 13.60.25-0.0625=2.55 eV (2) Lyman series :for shortest wavelength :n2 = E= 13.6(122-0) = 3.4 eV

  • -49
What are you looking for?