23 rd sum anyone plssss
ANS
Since no 2 ordered pairs in g have the same first component. So, g is a function such that g(1) = 1, g(2) =3 , g(3) = 5, g(4) =7.
It is given that g(x) = ax + b.
therefore g(1) = 1 gives a + b = 1
and g(2) = 3 gives 2a + b =3
which further gives a= 2 and b= -1
Since no 2 ordered pairs in g have the same first component. So, g is a function such that g(1) = 1, g(2) =3 , g(3) = 5, g(4) =7.
It is given that g(x) = ax + b.
therefore g(1) = 1 gives a + b = 1
and g(2) = 3 gives 2a + b =3
which further gives a= 2 and b= -1