23) The atwood machine has a third mass attached to it by a slack (light) string. After being released, the 2m mass falls a distance y = 8 3 m before the slack string becomes taut. Just after the slack string becomes taut the speed of masses is g x . Find X. (Assume that pulley is ideal and take acceleration due to gravity = g)

Dear student,

when the string was slack,

accelaration of the 2m and m blocks = (2mg-mg)/3m
​=g/3

distance=8/3 m

v2-u2=2asv2=2 (g/3) (8/3)v=4/3g
now, just after the string becomes taught, we can see by force analysis that external force on the system (of 3 blocks) is zero

hence the system moves with constant speed from now on.

thus x=4/3

Regards
 

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