24.  The time required to remove electrolytically one fourth of Ag from 0.2 litre of 0.1 M AgNO3 solution by a current of 0.1 amp. is :

1.  320 min.             2.  160 min.            3.  80 min.           4.  40 min.

Dear Student,

Total Ag+ ions= Concentration×Volume=0.1×0.2=0.02 molOne fourth of Ag+=14×0.02=5×10-3 molAg+ + e-  AgSo, for 1 mol of Ag+ quantity of electricity required is 1×96500 CFor 5×10-3 mol of Ag+ quantity of electricity required = 5×10-3×96500 CAlso,Q= ItSo, 5×10-3×96500 C = 0.1×tor, t=4825 s or 80.5 minHence, correct answer is (3)

  • -1
What are you looking for?