24g carbon on complete combustion produces how much volume of CO2 at STP?

DEAR STUDENT, 
For Combustion of carbon, reaction is 
C(s) + O₂ (g) $\to$ CO₂(g)
According to above equation,
1 Mole CARBON (12g) gives 1 mole (22.4L) CO₂ gas.
Then, 24 g Carbon will give $\frac{22.4L\times 24g}{12g}$= 44.8 L of CO₂ gas.
Hence, 44.8L of CO₂ is obtained.
Regards,