25.4 g of iodine and 14.2 g of chlorine are made to react completely to yield a mixture of ICl and ICl3. Calculate the number of moles of ICl and ICl3 formed.

Dear student!

Given that, I₂ + 2Cl₂ --> ICl + ICl₃ 

Now, we have, molar mass of  I₂ = 127 x2 = 254

Molar mass of  Cl₂ = 35.5x2 = 71

Moles of  I₂ used in the reaction = given mass/ molar mass = 25.4/ 254 = 0.1 moles of  I₂ 

Moles of  Cl₂ used in reaction = 14.2/ 71 =0.2 moles of  Cl₂ 

Here, from the reaction we see that, 1 mole of  I₂  reacts with 2 moles of  Cl₂ to give one mole of each of ICl and ICl₃ 

Interpreting the same data with the given sample we can conclude that, 0.2 mole of Cl₂ reacts with 0.1 mole of  iodine to give  0.1  mole of each of ICl and ICl_{3 .}