25.4 g of iodine and 14.2 g of chlorine are made to react completely to yield a mixture of ICl and ICl3. Calculate the number of moles of ICl and ICl3 formed.
Given that, I2 + 2Cl2 --> ICl + ICl3
Now, we have, molar mass of I2 = 127 x2 = 254
Molar mass of Cl2 = 35.5x2 = 71
Moles of I2 used in the reaction = given mass/ molar mass = 25.4/ 254 = 0.1 moles of I2
Moles of Cl2 used in reaction = 14.2/ 71 =0.2 moles of Cl2
Here, from the reaction we see that, 1 mole of I2 reacts with 2 moles of Cl2 to give one mole of each of ICl and ICl3
Interpreting the same data with the given sample we can conclude that, 0.2 mole of Cl2 reacts with 0.1 mole of iodine to give 0.1 mole of each of ICl and ICl3 .