25 horses eat 5 bags of corn in 12 days , how much will 10 horses eat in 18 days ?

Answer :

25 horses eat in 12 days total  5 bags
So,
1 Horse eat in 1 day total  $\frac{5}{25 \times 12} = \frac{1}{5 \times 12}$ bags
Therefore
10 horses eat in 18 days total $\frac{1}{5 \times 12}\times 10 \times 18 = \frac{10 \times 18}{5 \times 12} = \frac{2 \times 3}{2}=\mathbf{ }\mathbf{3}\mathbf{ }\mathit{b}\mathit{a}\mathit{g}\mathit{s}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{(}\mathbf{ }\mathit{A}\mathit{n}\mathit{s}\mathbf{ }\mathbf{)}$