2g of gas A introduced in a evacuated flask at flask at 25 degree celcius. The pressure of the gas is 1atm. now 3g of another gas B is introduced in the same flasks total pressure becomes 1.5atm. The ratio of molecular mass of A and B is?
3g of B = .5 atm => lets assume that this is x moles
2g of A = 1 atm => so this is 2x moles
2g/2x = ma (m = molecular mass) and 3g/x = mb
ma/mb = 2g/2x * x/3g = 2/2 * 1/3 = 1/3