(2x+3)/(3x+4)=(2x-3)/(3x-2)

\frac{2 x + 3}{3 x + 4} = \frac{2 x - 3}{3 x - 2} \Rightarrow (2 x + 3) (3 x - 2) = (2 x - 3) (3 x + 4) \Rightarrow 2 x (3 x - 2) + 3 (3 x - 2) = 2 x (3 x + 4) - 3 (3 x + 4) \Rightarrow 6 x^{2} - 4 x + 9 x - 6 = 6 x^{2} + 8 x - 9 x - 12 \Rightarrow 5 x - 6 = - x - 12 \Rightarrow 5 x + x = - 12 + 6 \Rightarrow 6 x = - 6 \Rightarrow x = - \frac{6}{6} \Rightarrow x = - 1

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