2x-3/x2-3x+2 find domain and range

x2 -3x + 2 = (x - 2)(x - 1) is not = 0
x is not = 1,2
Domain = R -{1,2}

Let the function f(x) = y 
therefore, 2x - 3 = x2y - 3xy + 2y
             ,  x2y + x(2 - y) + (2y + 3) = 0
               x = y -2 +-{ [(2 - y)2 - 4y(2y + 3)]1/2 }/2y
 
            y is not = o 
             4 + y2 - 4y - 8y- 12y > 0
            7y+ 16y - 4 < 0
            now solve for y and take out the range 

please give a helpful vote !!
  • -3
Dom= R-{1,2}
Range= R-{1,2}
  • -10
Answerr is given in the photo

  • -2
Lolz
  • -6
2^x-3/x^2-3x+2
  • 3
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