2x-3/x²-3x+2 find domain and range

x² -3x + 2 = (x - 2)(x - 1) is not = 0
x is not = 1,2
Domain = R -{1,2}

Let the function f(x) = y 
therefore, 2x - 3 = x²y - 3xy + 2y
             ,  x²y + x(2 - y) + (2y + 3) = 0
               x = y -2 +-{ [(2 - y)² - 4y(2y + 3)]^1/2 }/2y
 
            y is not = o 
             4 + y² - 4y - 8y² - 12y > 0
            7y² + 16y - 4 < 0
            now solve for y and take out the range 

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