√3-1)cosec 20+(√3+1) sec20=4√2 This question has not been answered yet! Don't worry! You can check out similar questions with solutions below Prove root 3 cosec 20 - sec 20= 4prove that : sec(70-A) = cosec(20+A)(Square root of 3) cosec 20? -sec 20? = 4 Solve : root 2 * cosec 20 degree *sec 20 degree = ? prove the following : root 3 cosec 20 - sec 20 = 4