3. A solution containing 10g per dm3 of Urea is isotonic with 5% of a nonvolatile solute . calculate gram molecular weight of non volatile solute

Dear Student,

The computation are expressed below,

moles of urea = 10 g60 gmol=0.167 molconcentration of urea = 0.167 mol 1 lt=0.167 Mby taking basis as 1000 ml 5% = 50 gm per ltmoles of unknown solute = 50m molconcentration of unknown solution = 50m molLnow by computing known and unknown we get,0.167 = 50mm = 299.401 gmol   (molar mass)
Regards.

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