3-ABC is anequilateral triangle.BD and CE are medians. show that BD= CE
ΔABC is an equilateral triangle. BD and CE are the medians of ΔABC.
ΔABC is an equilateral triangle.
∴ AB = AC (Sides of an equilateral triangle are equal)
⇒ BE = CD (BD and CD are medians of ΔABC)
In ΔBCE and ΔBCD,
BE = CD (Proved)
∠EBC = ∠DCB = 60°
BC = BC (Common)
∴ ΔBCE ΔBCD (SAS congruence criterion)
⇒ CE = BD (CPCT)