3 circles each of radius 3.5 cm are drawn in such a way that each of them touches the other two . find the area enclosed between these three cicles (shaded region )use pie=22/7?

i am unable to under stand this

No equilateral triangle is mentioned here. I don't know!

I got the answer!!!
If the circles just touch each other, then you can draw a line connecting the centres of each pair of adjacent circles creating an equilateral triangle of side length 7 (2 times 3.5). The area of an equilateral triangle is given by: 

 

There are four areas inside of this equilateral triangle, three  circle sectors and the area we seek. 

The area of a circle sector is given by: 

  where  is the central angle of the sector. 

So, the area we want is the area of the equilateral triangle minus three times the sector area. 


 

You just need to simplify but I would leave the answer in terms of the radical and  

I think the 3 circles are enclosed to form a triangle. Each side is 7cm... Then if all sides of a triangle are equal then every angles are also equal that means each angle is 60°.. Then by using area of equilateral triangle formula we will get the answer...

if three circles of radius a each are drawn such that each touches the other two
 

Here it is!

Area of the shaded region = Area of equilateral triangle - Areas of 3 sectors of 60 at vertices of triangle = rt.3/ 4 * 7 * 7 - (3 * 60/360 * 22/7 * 3.5 * 3.5) (side of equi. tri = 3.5 +3.5 = 7 cm ) = 49 rt3 / 4 - (11*5*35) /100 = 84.868/4 - 1925/100 = 21.217 - 19.25 = 1.967 cm2

Thanks anurag