3 cubes of edges 10 cm each are placed side by side nd stuck 2gether. if the outer surface alone is painted @2 p / cm2. Find the cost of painting.

Length of the resulting cuboid, l = (10 + 10 + 10) = 30 cm

Breadth of the resulting cuboid, b = 10 cm

Height of the resulting cuboid = 10 cm

S.A of the resulting cuboid = 2(lb + bh + hl) = 2(300 + 100 + 300) = 2(700) = 1400 cm2

Cost of painting of 1 cm2 = 2 paisa

Cost of painting of 1400 cm2 = 1400 × 2 = 2800 paisa = Rs.28

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 S.A = 6 (l)2

S.A= (6 * 10 * 10) cm = 600 cm2

S.A of 3 cubes together = (3 * 600) cm = 1800 cm2

Painting cost of 3 cubes = 2 * 1800 = 3600 p

In Rs. = 1 Rs = 100 p

= 1p = 1/100 Rs

= (3600/100) Rs = Rs. 36

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