3 persons A,B,C shoot to hit a target. If in trials À hits the target 4 times in 5 shots, B hits thrice in 4 shots and C hits 2 times in 3 trials. Find the probability that at least 2 persons hit the target.

Let E, F and G be the events that A hits the target, B hits the target and C hits the target respectively.Now, PE = 45 PA does not hit the target = PE = 1 - 45 = 15PF = 34 PB does not hit the target =PF = 1 - 34 = 14PG = 23 PC does not hit the target=PG = 1 - 23 = 13Required probability = PEFG + PEFG + PEFG + PEFG=PE.PF.PG + PE.PF.PG + PE.PF.PG + PEPFPG=45×34×13+45×14×23+15×34×23+45×34+23=1260 + 860+660+2460=5060=56

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