30) A car starts from rest and moves with uniform acceleration 'a'. At same instant from the same point a bike crosses with a uniform velocity 'u'. When and where will they meet? What is the velocity of car with respect to the bike at the time of meeting?

Dear Student
Distance travelled by cars = ut +12at2s=12at2t2=2saDistance travelled by bike in same time ts=utt=sut2=s2u2Equating both time2sa=s2u2s=2u2aTimet=2u2au=2ua
Velocity of car at time of meeting
v=at =a2ua=2uWith respect to bikev= 2u-u=u


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