30) A car starts from rest and moves with uniform acceleration 'a' At same instant from the same point - Physics - Motion in one dimension

Question

30) A car starts from rest and moves with uniform acceleration 'a'
At same instant from the same point a bike crosses with a uniform
velocity 'u' When and where will they meet? What is the velocity of
car with respect to the bike at the time of meeting?

Vipra Mishra · Accepted Answer

Dear Student
Distance travelled by cars = ut +12at2s=12at2t2=2saDistance travelled by bike in same time ts=utt=sut2=s2u2Equating both time2sa=s2u2s=2u2aTimet=2u2au=2ua
Velocity of car at time of meeting
v=at =a2ua=2uWith respect to bikev= 2u-u=u

Regards

30) A car starts from rest and moves with uniform acceleration 'a'. At same instant from the same point a bike crosses with a uniform velocity 'u'. When and where will they meet? What is the velocity of car with respect to the bike at the time of meeting?