31 question please Q31. Ramu had 13 notes in the denominations of Rs. 10, Rs. 50 and Rs. 100. The total value of the notes with him was Rs. 830. He had more of Rs. 100 notes than that of Rs.50 notes him. Find the number of Rs. 10 notes with him . (a) 4 (b) 3 (c) 2 (d) 5 Share with your friends Share 8 Abhishek Kr. Jha answered this Dear student, Here is the solution of your asked query: Let, number of Rs.50 notes be x and number of Rs.100 notes be y.And total number of notes = 13Then, number of Rs.10 notes =13-x+ySo, value of x notes of Rs.50=50xValue of y notes of Rs.100=100yAnd value of 13-x+y notes of Rs.10=13-x+y×10So, total value of these notes = 50x+100y+13-x+y×10And it is given that total value of these notes is Rs.830. So we have;50x+100y+13-x+y×10=830⇒50x+100y+130-10x-10y=830⇒40x+90y=700⇒4x+9y=70Now, there are two variables and one equation. So here we use hit and trial method to find the value of x and y.Also, considering the condition that number of Rs.100 notes is more that Rs.50 notes i.e. y>xUsing hit and trial method, put x=1 we have;4×1+9y=70⇒y=669 which is in fractions and can't take as number of notes.Now, putting x=2 we have;4×2+9y=70⇒y=629 which is also in fraction.Putting x=4 we have;4×4+9y=70⇒9y=54⇒y=6So by putting x=4, we have y=6 which also satisfies the condition y>x.So, number of Rs.50 notes = 4And number of Rs.100 notes = 6Then number of Rs.10 notes = 13-4+6=3 Regards 7 View Full Answer Saumitra Kumar answered this b) 3 -4
