33 (a) The figure (i) given below is a trapezium. Find the length of BC and the area of the trapezium. Assume AB = 5 cm, AD = 4 cm, CD = 8 cm.
const a line BE perpendicular to CD & AB.
BE=4cm
CE=CD-DE
CE=8cm-5cm=3cm
BC2=CE2+BE2
BC2=9+16
BC2=25
BC=5cm
Area of trapezium ABCD=1/2*(sum of parallel sides)*distance between the parallel sides
Area of trapezium ABCD=1/2*(5+8)*4
Area of trapezium ABCD=13*2
Area of trapezium ABCD=26cm2
Therefore, area of the trapezium is 26sqcm and measure of its side BC is 5cm.
BE=4cm
CE=CD-DE
CE=8cm-5cm=3cm
BC2=CE2+BE2
BC2=9+16
BC2=25
BC=5cm
Area of trapezium ABCD=1/2*(sum of parallel sides)*distance between the parallel sides
Area of trapezium ABCD=1/2*(5+8)*4
Area of trapezium ABCD=13*2
Area of trapezium ABCD=26cm2
Therefore, area of the trapezium is 26sqcm and measure of its side BC is 5cm.