36500J of heat is given to 500g of a liquid at 35(degree)c. If the specific heat capacity of the liquid is 2000J/kg'C, calculate it's final temperature

Dear Student,
Q = m × c × ∆T
Q = Heat transferred
M –Mass of the substance
C – Specific heat capacity
T – Change in temperature (in Celsius)
∆T – Final temperature  -  initial temperature
According to quation 
Q = 36500J
m = 500 g = 0.5 Kg
c = 2000 J/Kg oC
Ti = 35o C
Tf = ?


So,
Q = m × c × (Tf – Ti)
(Tf – Ti) = Q/ m × c
(Tf – Ti) = 36500/(0.5 × 2000)
(Tf – Ti) = 36500/1000
(Tf – Ti) = 36.5
Tf = 36.5 + 35
Tf = 71.5o C


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