37 A block of mass 5 kg slides down on an inclined plane of inclination 30 from - Physics - Work Energy And Power

Question

37 A block of mass 5 kg slides down on an inclined plane of
inclination 30 ° from a height of 10 m from ground The
coefficient of friction between the block and the inclined plane is
0 5 Find the work done by friction on the block
A )     250 3 J            
    B )     - 250 3   J    
                C )  
  500   J            
        D )     - 500   J

Sanjay Singh · Accepted Answer

Dear student

sin30°=10Length of the plankLength of the plank=10sin30°=10×2=20mforce of friction is f=μN=μmgcosθf=0
5×5×10×cos30°=25×32work done by friction is W=-f×(Length of the plank)=-25×32×20=-2503JRegards

37. A block of mass 5 kg slides down on an inclined plane of inclination 30 ° from a height of 10 m from ground. The coefficient of friction between the block and the inclined plane is 0.5. Find the work done by friction on the block. A ) 250 3 J B ) - 250 3 J C ) 500 J D ) - 500 J

37. A block of mass 5 kg slides down on an inclined plane of inclination 30 $°$ from a height of 10 m from ground. The coefficient of friction between the block and the inclined plane is 0.5. Find the work done by friction on the block.
$A) 250 \sqrt{3} J B) - 250 \sqrt{3} J C) 500 J D) - 500 J$