3a-4b find square

Hello Purna dear, (3a - 4b)^2 = (3a)^2 - 2 * (3a) * (4b) + (4b)^2 = 9 a^2 - 24 ab + 16 b^2
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(3a - 4b)2
Using the given identity, we can solve this question:
(a - b)2 = a2 + b2 - 2ab
   (3a - 4b)2
= (3a)2 + (4b)2 - 2(3a)(4b)
= 9a​2 + 16b2 - 24ab
​This is the equation we obtain on solving the above sum.
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(3a-4b)2
=(3a)2-2*3a*4b+(4b)2
=9a2-24ab+16b2
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I don't know
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