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4(2a-3b)^₂-(2b-c)²

$4 {(2 a - 6 b)}^{2} - (2 b - c)^{2} = [2 (2 a - 3 b)]^{2} - [2 b - c]^{2} = [2 (2 a - 3 b) + (2 b - c)] [2 (2 a - 3 b) - (2 b - c)] [using: a^{2} - b^{2} = (a + b) (a - b)] = (4 a - 6 b + 2 b - c) (4 a - 6 b - 2 b + c) = (4 a - 4 b - c) (4 a - 8 b + c)$

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