4.8 g of nitrogen was compressed isothermally and reversibly from 100 Nm-2 to 5 atm at 300K .Calculate the work obtained .

The work done of a reversible isothermal expansion Wmax = -2.303 nRT log P1P2R= 8.314 JT = 300 Kn= Mass in gMolar mass = 4.828 = 0.1714 molP1 = 100 Nm-2 = 0.000986923 atmP2 = 5 atmWmax = -2.303 × 0.1714 × 8.314 × 300× log 0.0009865   = 3647.86 J     = 3.648 kJ

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1st caclulate no of moles(n) of N2 by formula n = Weight/Mole. wt... Now use the formula for Wmax = -2.303nRTlog(P1/P2)
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