4) Equation of the tangent to the circle, at the point (1,-1) whose centre is the point of intersection of - Maths - Conic Sections

Question

4 )   E q u a t i o n   o f   t h e   tan g e n
t   t o   t h e   c i r c l e ,   a t   t
h e   p o i n t   ( 1 , - 1 )   w h o s e   c e
n t r e   i s   t h e   p o i n t   o f  
i n t e r s e c t i o n   o f   t h e s t r a i g h t
  l i n e   x - y = 1   a n d   2 x + y = 3
  i s ( A )   3 x - y - 4 = 0        
                  ( B
)   x + 4 y + 3 = 0            
            ( C )   x - 3 y - 4
= 0

Ankita Agarwal · Accepted Answer

Dear Student,

Hence option (B) is correct

Regards

4 ) E q u a t i o n o f t h e tan g e n t t o t h e c i r c l e , a t t h e p o i n t ( 1 , - 1 ) w h o s e c e n t r e i s t h e p o i n t o f i n t e r s e c t i o n o f t h e s t r a i g h t l i n e x - y = 1 a n d 2 x + y = 3 i s ( A ) 3 x - y - 4 = 0 ( B ) x + 4 y + 3 = 0 ( C ) x - 3 y - 4 = 0

$4) E q u a t i o n o f t h e \tan g e n t t o t h e c i r c l e, a t t h e p o i n t (1, - 1) w h o s e c e n t r e i s t h e p o i n t o f i n t e r s e c t i o n o f t h e s t r a i g h t l i n e x - y = 1 a n d 2 x + y = 3 i s (A) 3 x - y - 4 = 0 (B) x + 4 y + 3 = 0 (C) x - 3 y - 4 = 0$