4. The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?
(a) The oxidation number of hydrogen is always +1. (b) The algebraic sum of all the oxidation numbers in a compound is zero. (c) An element in the free or the uncombined state bears oxidation number zero. (d) In all its compounds, the oxidation number of fluorine is –1.

Dear student,

​​​​​1. The oxidation state of hydrogen  is +1  always. This statement is True but this statement is not always true as we have some exceptions when the hydrogen is attached with metals like sodium , then its oxidation state changes to -1.

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2.The  algebraic sum of all the oxidation states in a compound is zero. This Statement is also True. For example-
In H2SO4;
 2(+1) + S+4(-2) =O
S=+6

So, in this example the Sulphur must be +6 to give a sum kf +6

3. When an element is in uncombined state or in free State its oxidation state is zero. So, this statement is also True.
 But we have some exceptions as 
For a monoatomic ion, the oxidation state is equal to the net charge on the ion. For eg.
In Cl the chlorine has an oxidation state of -1
But in Clthe oxidation state is zero.

4.  Flourine being a helogen and electronegative atoms shows an oxidation state of-1 in all its compound .
This statement is True.

So, we can say that these statements are true to some extents with some exceptions.


Regards!!!!

Regards!!!!!
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