400 ml each of H2 and O2 are ignited, find the volume of water vapour formed. Share with your friends Share 2 Vartika Jain answered this Dear Student, H2(g) + 12O2(g) → H2O(g)1 mol i.e. 22.4 L of H2 reacts with 0.5 mol i.e. 22.4×0.5 L of O2So, 400 ml or 0.4L of H2 will react with 22.4×0.5 22.4×0.4=0.2 L of O2Therefore, H2 is the limiting reagent. Now, 22.4 L of H2 gives 22.4 L of H2OSo, 0.4L of H2 will give 0.4 L of H2OHence, volume of water vapour formed is 0.4 L or 400 ml. 0 View Full Answer