42. what is amount of charge required to liberate 11.5 g of NaCl Share with your friends Share 0 Geetha answered this According to Faraday I laww = ZQw= atomic massn × F × Qw= atomic massn= number of electronsF= faradayQ = charge11.5 = 231 × 96500× QQ= 48250 Coulomb. Thus the amount of charge = 48250 Coulomb. 96500 coulomb = 1 Faraday So 48250 coulomb = 0.5 Faraday -1 View Full Answer
