42. what is amount of charge required to liberate 11.5 g of NaCl

According to Faraday I laww = ZQw= atomic massn × F × Qw= atomic massn= number of electronsF= faradayQ = charge11.5 = 231 × 96500× QQ= 48250 Coulomb. Thus the amount of charge = 48250 Coulomb. 
96500 coulomb = 1 Faraday 
So 48250 coulomb = 0.5 Faraday

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