46 and 49 Share with your friends Share 0 Vartika Jain answered this Dear Student, 46) The correct answer is (3)No. of electrons in O22- = 18 =σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2π*2px2π*2py2Bond order=Nb-Na2=10-82=22=1No. of electrons in B2 =10 = σ1s2σ*1s2σ2s2σ*2s2π2px1π2py1Bond order=Nb-Na2=6-42=22=1Kindly ask the remaining query in the next thread. 0 View Full Answer