4gm of a mixture of caco3 and sand sio2 is treated with excess of hcl then 0.88gm of co2 is produced . What is % of caco3 Share with your friends Share 0 Animesh Paul answered this Dear student, The reactions are as follows - CaCO3 + 2HCl →CaCl2 + H2O + CO2SiO2 + HCl → No reactionLet take the mass of pure CaCO3 = x gram From the above reaction - 100 gram CaCO3 gives → 44 gram CO2x gram CaCO3 gives → 0.88 gram CO2⇒ 100x = 440.88⇒ x = 2 gramsPercent of limestone = 24×100 = 50 % Regards 1 View Full Answer