4gm of a mixture of caco3 and sand sio2 is treated with excess of hcl then 0 88gm of co2 - Chemistry - Some Basic Concepts of Chemistry

Question

4gm of a mixture of caco3 and sand sio2 is treated with excess of
hcl then 0 88gm of co2 is produced What is % of caco3

Animesh Paul · Accepted Answer

Dear student,

The reactions are as follows - CaCO3 + 2HCl →CaCl2 + H2O + CO2SiO2 + HCl → No reactionLet take the mass of pure CaCO3 = x gram From the above reaction - 100 gram CaCO3 gives → 44 gram CO2x gram CaCO3 gives → 0
88 gram CO2⇒ 100x = 440
88⇒  x = 2 gramsPercent of limestone = 24×100 = 50 %

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4gm of a mixture of caco3 and sand sio2 is treated with excess of hcl then 0.88gm of co2 is produced . What is % of caco3