4sin(π/3- theta)sin(π/3+theta)= 3- 4sin^theta. ( Prove)

Dear Student, We know that 2sinx+ysinx-y= cos2y-cos2xNow, 2×2sinπ3+θsinπ3-θ= cos2θ-cos2×π3= cos2θ--12= 12+1-2sin2θ= 3-4sin2θ2Regards

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