4x2 + 4bx - (a2 - b2 ) = 0 please solve this equation................

The given quadratic is 4x2 + 4bx – (a2b2) = 0

Thus, the solutions of given equations are .

  • 77

4x²+4bx+(a²-b²)

= 4x²+2(b+a)x +2(b-a)x+(a+b)(a-b)

= 2x(2x+a+b)+(b-a)(2x+a+b)

= (2x+a+b)(2x+b-a)

=> x= -b-a/2 , =>x=a-b/2

  • -8

4x²+4bx-(a²-b²)

= 4x²+2(b+a)x +2(b-a)x-(a+b)(a-b)

= 2x(2x+a+b)-(b-a)(2x+a+b)

= (2x+a+b)(2x-b+a)

=> x= -b-a/2 , =>x=b-a/2 , i hope its ri8 now!

  • 24
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