5. The van is moving on a horizontal ground along a straight road as shown in figure. The velocity of Van is given as : v = (9t - t2 +10) m/s, where t is in second Coefficient of friction between the wall of van and block of m kg is u. The block is at rest w.r.t. van initially. The friction time graph between block and van is given as (g = 10 m/s2). (A) The value of mass of block is 10 kg (B) The coefficient of friction (u) is 2 (C) The acceleration of block at t = 3 sec is 5 m/sec.2 (D) The coefficient of friction (u) is 1 Share with your friends Share 7 Shobhit Mittal answered this Dear Student, v=9t-t2+10a=9-2taccn becomes zero at t=4.5 secthe friction force required to balance the body =mgat t=0a=9the mass of the body should be 10 kg as it friction is 100 N m=10kg option A is correct .at t=2 a=5 50μ=100μ=2 option B is correct .downward accn =100-2*10*310=4horizontal accn =3 from the accn eqn at t=3net accn =16+9=5 m/s2option C is correct .option d is incorrect as option B is correct.Regardsv=9t-t2+10a=9-2taccn becomes zero at t=4.5 secthe friction force required to balance the body =mgat t=0a=9the mass of the body should be 10 kg as it friction is 100 N m=10kg option A is correct .at t=2 a=5 50μ=100μ=2 option B is correct .downward accn =100-2*10*310=4horizontal accn =3 from the accn eqn at t=3net accn =16+9=5 m/s2option C is correct .option d is incorrect as option B is correct.Regards 2 View Full Answer
