500 ml of aM solution and 250ml of bM solution of the same solute are mixed and diluted to 2L.The diluted solution shows the molarity 1.6m.If a:b is 2:5 then calculate a and b.

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M1V1+M2V2=M3(V1+V2)or, a×500+b×250=M3(500+250)or, 500 a+ 250 b= 750 M3     ..(i)and, M3(V1+V2) = M4V4or, 750M3=1.6×2000or M3=4.26MTherefore, 500 a+250 b=750×4.26 =3200or, 50a + 25b=320Dividing by b, we get50ab+25=320ba:b=2:5or, 50×25+25=320bor, b=7.11and  50a + 25×7.11=320or, 50 a=320-177.77or, a=2.84

 

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