50g of ice at 0 degree c is mixed with 50g water at 2o degree c the resultant temperature of the mixture would be

Suppose the resulting temperature is .

According to the principle of calorimetry

Heat lost by water=Heat gained by ice---(i)

Heat lost by water=

(Here L=80cal/g and specific heat of water=1cal/g/0C)

Hope this will help you to solve the question.

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