50g of ice at 0 degree c is mixed with 50g water at 2o degree c the resultant temperature of - Physics -

Question

50g of ice at 0 degree c is mixed with 50g water at 2o degree c
the resultant temperature of the mixture would be

Jyoti Pant · Accepted Answer

Suppose the resulting temperature is $T_{0}$ .

According to the principle of calorimetry

Heat lost by water=Heat gained by ice---(i)

Heat lost by water=

$m_{w} s_{w} (T_{1} - T_{2}) = 50 \times 1 \times (20 - T_{0}) H e a t g a i n e d b y i c e = m_{i} L + m_{i} s_{w} (T_{0} - 0) N o w b y p u t t i n g t h e v a l u e s f o r (i) y o u c a n g e t t h e a n s w e r .$

(Here L=80cal/g and specific heat of water=1cal/g/0C)

Hope this will help you to solve the question.

50g of ice at 0 degree c is mixed with 50g water at 2o degree c the resultant temperature of the mixture would be