50kg of bag is lifted to 10th floor30m high what is the work done in lifting? What is its speed and Kinetic energy at the ground level is the bag is dropped from there

Dear Student,
GIVEN: m=50 kg , distance = 30 m 

Work done = $force \times dis\tan ce$
Force = mg 
F = $50\times 9.8$ = 490 N
Work done = $490\times 30$ = 14700 J
Kinetic energy at ground = potential energy at maximum height  =mgh
Kinetic energy = $50\times 9.8\times 30$ = 14700 Joules 
We know that kinetic energy = $\frac{1}{2}m{v}^2$
v=$\sqrt{\frac{2KE}{m}}=\sqrt{\frac{2\times 14700}{50}}$
v= 24.24 m/s
Regards!