59. The value of x, $\log_{e}$ (x-3) <1 is
a) (0,3)
b) (0,e)
c) (0, e+3)
d) (3,3+e)

\log_{e} (x - 3) < 1 \log (x - 3) < \log (e^{1}) [∵ a = \log (e^{a})] x - 3 < e and x - 3 > 0 [As if a > 1 then \log_{a} (f (x)) < \log_{a} (g (x)) is equivaleny to f (x) < g (x) and f (x) > 0] x < e + 3 and x > 3 x \in (3, e + 3)

59. The value of x, log e (x-3) <1 is a) (0,3) b) (0,e) c) (0, e+3) d) (3,3+e)