5g of ice at 0?C and 20g of water at 45?C are mixed. The temperature of mixture will be? Share with your friends Share 0 Anshu Agrawal answered this Dear student, Let the final temperature be T Heat Given = Heat TakenQ= mc∆T5×80+5×1×(T−0)=20×(45−T)×1 ⇒400+5T=900−20T ⇒20T+5T=900−400 ⇒T=20℃ Regards 0 View Full Answer
