5SIN62/COS28 - 2SEC34/COSEC 56

5 sin 62 / cos 28 - (2 sec 34 / cosec 56)
= 5 sin (90-28)/cos 28 - [2 sec( 90-56)/ cosec 56]
= 5 cos 28/cos 28 - ( 2 cosec 56/cosec 56)
= 5 -2
= 3
  • 1
From the given figure, find the value of AC, sinB and tanC
  • -1
What are you looking for?